Percentage
कुल प्रश्न: 40 | पेज 2
11. . In an election between two candidates, the winning candidate got 60% of the total votes and won by a majority of 2400 votes. What was the total number of votes polled?
सही उत्तर: [D]
हल (Solution):
Correct Answer: B) 12000
Solution:
Winner got 60%, so Loser got (100 - 60) = 40%.
Difference in percentage = 60% - 40% = 20%.
20% of Total Votes = 2400 => Total Votes = (2400 * 100) / 20 = 12000.
Correct Answer: B) 12000
Solution:
Winner got 60%, so Loser got (100 - 60) = 40%.
Difference in percentage = 60% - 40% = 20%.
20% of Total Votes = 2400 => Total Votes = (2400 * 100) / 20 = 12000.
12. A student has to secure 40% marks to pass an exam. He gets 178 marks and fails by 22 marks. What are the maximum marks of the exam?
सही उत्तर: [B]
हल (Solution):
Correct Answer: B) 500
Solution:
Passing Marks = Marks obtained + Failing marks = 178 + 22 = 200.
40% of Maximum Marks = 200.
Maximum Marks = (200 * 100) / 40 = 500.
Correct Answer: B) 500
Solution:
Passing Marks = Marks obtained + Failing marks = 178 + 22 = 200.
40% of Maximum Marks = 200.
Maximum Marks = (200 * 100) / 40 = 500.
13. . If the price of petrol is increased by 25%, by how much percentage should a consumer reduce his consumption so that his expenditure remains unchanged?
सही उत्तर: [A]
हल (Solution):
Correct Answer: A) 20%
Solution:
Required reduction % = [R / (100 + R)] * 100
= [25 / (100 + 25)] * 100 = (25/125) * 100 = 20%.
Correct Answer: A) 20%
Solution:
Required reduction % = [R / (100 + R)] * 100
= [25 / (100 + 25)] * 100 = (25/125) * 100 = 20%.
14. The population of a town increases by 10% annually. If its present population is 20,000, what will be its population after 2 years?
सही उत्तर: [C]
हल (Solution):
Correct Answer: C) 24,200
Solution:
Population after 2 years = Present Population * (1 + R/100)^2
= 20000 * (110/100) * (110/100) = 20000 * 1.21 = 24,200.
Correct Answer: C) 24,200
Solution:
Population after 2 years = Present Population * (1 + R/100)^2
= 20000 * (110/100) * (110/100) = 20000 * 1.21 = 24,200.
15. 45% of a number is 135. What is 80% of that number?
सही उत्तर: [B]
हल (Solution):
Correct Answer: B) 240
Solution:
45% = 135 => 1% = 135 / 45 = 3.
Therefore, 80% = 3 * 80 = 240
Correct Answer: B) 240
Solution:
45% = 135 => 1% = 135 / 45 = 3.
Therefore, 80% = 3 * 80 = 240
16. Out of his total income, Mr. Sharma spends 20% on house rent and 70% of the rest on household expenses. If he saves Rs. 3,600, what is his total income?
सही उत्तर: [A]
हल (Solution):
Correct Answer: A) Rs. 15,000
Solution:
Let total income be 100. Rent = 20, Remaining = 80.
Household expenses = 70% of 80 = 56.
Total savings = 80 - 56 = 24.
If 24 units = 3600, then 100 units = (3600 / 24) * 100 = Rs. 15,000.
Correct Answer: A) Rs. 15,000
Solution:
Let total income be 100. Rent = 20, Remaining = 80.
Household expenses = 70% of 80 = 56.
Total savings = 80 - 56 = 24.
If 24 units = 3600, then 100 units = (3600 / 24) * 100 = Rs. 15,000.
17. An alloy contains 32% copper, 24% zinc and the rest is nickel. How much nickel is present in 5 kg of the alloy?
सही उत्तर: [A]
हल (Solution):
Correct Answer: A) 2.2 kg
Solution:
Percentage of Nickel = 100% - (32% + 24%) = 100% - 56% = 44%.
Amount of Nickel in 5 kg = 44% of 5 kg = (44/100) * 5 = 2.2 kg.
Correct Answer: A) 2.2 kg
Solution:
Percentage of Nickel = 100% - (32% + 24%) = 100% - 56% = 44%.
Amount of Nickel in 5 kg = 44% of 5 kg = (44/100) * 5 = 2.2 kg.
18. If 80% of A = 50% of B and B = x% of A, then the value of x is:
सही उत्तर: [C]
हल (Solution):
Correct Answer: C) 160
Solution:
(80/100) * A = (50/100) * B => 8A = 5B => B = (8/5)A.
Given B = (x/100) * A => (8/5)A = (x/100) * A => x = (8/5) * 100 = 160
Correct Answer: C) 160
Solution:
(80/100) * A = (50/100) * B => 8A = 5B => B = (8/5)A.
Given B = (x/100) * A => (8/5)A = (x/100) * A => x = (8/5) * 100 = 160
19. The price of an item is first increased by 10% and then decreased by 10%. What is the net change in the price?
सही उत्तर: [C]
हल (Solution):
Correct Answer: C) 1% decrease
Solution:
Net change formula: A + B + (AB/100)
= 10 - 10 + [(10 * -10) / 100] = 0 - 1 = -1% (1% decrease).
Correct Answer: C) 1% decrease
Solution:
Net change formula: A + B + (AB/100)
= 10 - 10 + [(10 * -10) / 100] = 0 - 1 = -1% (1% decrease).
20. In a test, a candidate securing 30% marks fails by 5 marks, while another candidate who secures 40% marks gets 10 marks more than the passing marks. The minimum marks required to pass are:
सही उत्तर: [A]
हल (Solution):
Correct Answer: A) 50
Solution:
Difference in percentage = 40% - 30% = 10%.
Difference in marks = 10 - (-5) = 15 marks.
10% = 15 => Total Marks = 150.
Passing marks = 30% of 150 + 5 = 45 + 5 = 50.
Correct Answer: A) 50
Solution:
Difference in percentage = 40% - 30% = 10%.
Difference in marks = 10 - (-5) = 15 marks.
10% = 15 => Total Marks = 150.
Passing marks = 30% of 150 + 5 = 45 + 5 = 50.